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1 month agoAn “exponential drop” would be a drop that follow an exponential curve, but this doesn’t. What you mean is a “drop in the exponent”, which however doesn’t sound as nice.
An “exponential drop” would be a drop that follow an exponential curve, but this doesn’t. What you mean is a “drop in the exponent”, which however doesn’t sound as nice.
and not an exponential speed-up (O(2^n) to O(n): exponential to linear)
Note that you can also have an exponential speed-up when going from O(n) (or O(n^2) or other polynomial complexities) to O(log n). Of course that didn’t happen in this case.
Looks like the delay in 2011 was so big the data became available after the 2017 one